document.write( "Question 1131477: An angle measures 6° less than the measure of a complementary angle. What is the measure of each angle?
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Algebra.Com's Answer #748161 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( " complementary angles two angles whose sum is \"90\"°\r
\n" ); document.write( "\n" ); document.write( "if one angle is \"alpha\", a complementary angle will be \"beta\"\r
\n" ); document.write( "\n" ); document.write( " \"alpha%2Bbeta=90\"°\r
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\n" ); document.write( "\n" ); document.write( "if angle \"alpha\" measures \"6\"° less than the measure of a complementary angle,we have\r
\n" ); document.write( "\n" ); document.write( "\"alpha=beta-6\"\r
\n" ); document.write( "\n" ); document.write( "\"beta=alpha%2B6\"\r
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\n" ); document.write( "\n" ); document.write( "and, we have\r
\n" ); document.write( "\n" ); document.write( "\"alpha%2Balpha%2B6=90\"\r
\n" ); document.write( "\n" ); document.write( "\"2alpha=90-6\"\r
\n" ); document.write( "\n" ); document.write( "\"2alpha=84\"\r
\n" ); document.write( "\n" ); document.write( "\"alpha=42\"\r
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\n" ); document.write( "\n" ); document.write( "and, a complementary angle will be\r
\n" ); document.write( "\n" ); document.write( "\"beta=42%2B6\"\r
\n" ); document.write( "\n" ); document.write( "\"beta=48\"\r
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