document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1131439>Question 1131439</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Simplify\r<BR>\n" );
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document.write( "a) &#8730;(32k^(7)q^(8))\r<BR>\n" );
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document.write( "b)³&#8730;(-64a^(8)) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #748111 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=748111\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> break it apart <BR>\n" );
document.write( "sqrt(32)=sqrt(2)(sqrt(16))=4 sqrt(2)<BR>\n" );
document.write( "every 2 in an exponent under the radical (if square root) may be removed and become the variable to the first power.  sqrt(k^7) becomes k^3*sqrt(k), the remainder left behind.<BR>\n" );
document.write( "sqrt(q^8)=q^4.<BR>\n" );
document.write( "multiply everything together to get 4*k^3*q^4*sqrt(2k), noting how the two radical terms are just combined under one radical\r<BR>\n" );
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document.write( "do the same for cube roots<BR>\n" );
document.write( "cube root of -64 is -4<BR>\n" );
document.write( "for cube root of a^8, pull THREE a's out and make it the variable to the first power.<BR>\n" );
document.write( "cube root of a^8=a^2*cube root (a^2), the remainder is 2.<BR>\n" );
document.write( "This is -4a^2 cube root (a^2)<BR>\n" );
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