document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1131437>Question 1131437</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If two consecutive angles of a parallelogram are in the ratio 2:3,find the measure of each angle of the parallelogram<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #748101 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=748101\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two consecutive angles of a parallelogram add up to 180 deg.<BR>\n" );
document.write( "The ratio of the angles = 2/3.<BR>\n" );
document.write( "Let x = the larger angle<BR>\n" );
document.write( "Thus x + (2/3)x = 180<BR>\n" );
document.write( "Solving for x gives x = (3/5)180 = 108<BR>\n" );
document.write( "Therefore the smaller angle = (2/3)108 = 72<BR>\n" );
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