document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1131399>Question 1131399</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the ratio of the perimeter of ABCD to the perimeter of TVYN is 5/7, what is the ratio of AD/TN </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #748091 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=748091\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "The question can't be answered as you show it....<br><BR>\n" );
document.write( "Now, if it is true that ABCD and TVYN are similar figures, then the answer is easy.<br><BR>\n" );
document.write( "The ratio between any given pair of corresponding linear measurements between two similar figures is the ratio between ALL corresponding linear measurements.<br><BR>\n" );
document.write( "Specifically, if the ratio of the perimeters is 5/7 and the figures are similar, then the ratio of AD to TN is also 5/7. </SPAN>\n" );
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