document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1131402>Question 1131402</A>: <I><SPAN STYLE=\"word-break: break-all;\"> ABCD~TVYN<BR>\n" );
document.write( "If AB/TV = 8/5 and the perimeter of TVYN is 65, what is the perimeter of ABCD? \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #748089 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=748089\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "The figures are similar; the scale factor between one pair of corresponding sides is the same as the scale factor between all the other pairs of corresponding sides.  (In fact it is the scale factor between ANY corresponding linear measurements between the two figures.)<br><BR>\n" );
document.write( "The perimeter of ABCD is 65*(8/5) = 104. </SPAN>\n" );
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