document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1131389>Question 1131389</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 5(x+999) = -7(y+23322)<BR>\n" );
document.write( "(2k+1)(y+23322) = k(x+999)<BR>\n" );
document.write( "I just need to know which value of \"k\" will make the equation have infinitely many solutions. Can someone give me a step by step because I am lost here. Thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #748054 by </B><A HREF=/tutors/aboutme.mpl?userid=JoelSchwartz><B>JoelSchwartz(130)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JoelSchwartz><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=748054\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5(x+999)=-7(y+23322)<BR>\n" );
document.write( "(x+999)=(-7(y+23322))/5<BR>\n" );
document.write( "((x+999))/(y+23322)=-7/5<BR>\n" );
document.write( "(2k+1)(y+23322)=k(x+999)<BR>\n" );
document.write( "(2k+1)=k(x+999)/(y+23322)<BR>\n" );
document.write( "2k+1=k*-7/5<BR>\n" );
document.write( "10k+5=-7k<BR>\n" );
document.write( "17k=-5<BR>\n" );
document.write( "k=-5/17 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );