document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1131362>Question 1131362</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A piece of pottery is removed from a kiln and allowed to cool in a controlled environment. The temperature (in degrees Fahrenheit) of the pottery after it is removed from the kiln for various times (in minutes) is shown in the following table.<BR>\n" );
document.write( "Time (min)	Temperature (°F)<BR>\n" );
document.write( "15	2000<BR>\n" );
document.write( "20	1950<BR>\n" );
document.write( "30	1850<BR>\n" );
document.write( "60	1550<BR>\n" );
document.write( "(a) Find a linear model for the temperature of the pottery after t minutes.<BR>\n" );
document.write( "T(t) =__________?<BR>\n" );
document.write( "(b) Explain the meaning of the slope of this line in the context of the problem.<BR>\n" );
document.write( "The value of the slope means that the temperature is decreasing at a rate of  <BR>\n" );
document.write( " _________°F per minute.?<BR>\n" );
document.write( "(c) Assuming the temperature continues to decrease at the same rate, what will be the temperature of the pottery in 3 hours?_______°F? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #748026 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=748026\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> It changes by -50 degrees in 5 minutes, -100 degrees in 10 minutes or -10 degrees per minute<BR>\n" );
document.write( "point slope formula y=y1=m(x-x1) m slope (10 deg F  per minute) and (x1, y1) a point<BR>\n" );
document.write( "T(t)-2000=-10(t-15)<BR>\n" );
document.write( "T(t)=-10t+2150<BR>\n" );
document.write( "slope is cooling per minute<BR>\n" );
document.write( "in 3 hours, or 180 minutes, it will cool 1800 degrees or to 350 deg F (2150-1800) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );