document.write( "Question 1131309: Solve the system of equations using matrices. Use Gaussian elimination with back-substitution.
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document.write( "x + y + z = -5
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document.write( "x - y + 3z = -1
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document.write( "4x + y + z = -2
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Algebra.Com's Answer #747992 by ikleyn(52803)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( "Answer. x = 1 \r\n" ); document.write( " y = -4 \r\n" ); document.write( " z = -2 \r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "Solution\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "Your matrix\r\n" ); document.write( "\r\n" ); document.write( " X1 X2 X3 b\r\n" ); document.write( "1 1 1 1 -5\r\n" ); document.write( "2 1 -1 3 -1\r\n" ); document.write( "3 4 1 1 -2\r\n" ); document.write( "\r\n" ); document.write( "Find the pivot in the 1st column in the 1st row\r\n" ); document.write( "\r\n" ); document.write( " X1 X2 X3 b\r\n" ); document.write( "1 1 1 1 -5\r\n" ); document.write( "2 1 -1 3 -1\r\n" ); document.write( "3 4 1 1 -2\r\n" ); document.write( "\r\n" ); document.write( "Subtract the 1st row from the 2nd row\r\n" ); document.write( "\r\n" ); document.write( " X1 X2 X3 b\r\n" ); document.write( "1 1 1 1 -5\r\n" ); document.write( "2 0 -2 2 4\r\n" ); document.write( "3 4 1 1 -2\r\n" ); document.write( "\r\n" ); document.write( "Multiply the 1st row by 4\r\n" ); document.write( "\r\n" ); document.write( " X1 X2 X3 b\r\n" ); document.write( "1 4 4 4 -20\r\n" ); document.write( "2 0 -2 2 4\r\n" ); document.write( "3 4 1 1 -2\r\n" ); document.write( "\r\n" ); document.write( "Subtract the 1st row from the 3rd row and restore it\r\n" ); document.write( "\r\n" ); document.write( " X1 X2 X3 b\r\n" ); document.write( "1 1 1 1 -5\r\n" ); document.write( "2 0 -2 2 4\r\n" ); document.write( "3 0 -3 -3 18\r\n" ); document.write( "\r\n" ); document.write( "Make the pivot in the 2nd column by dividing the 2nd row by -2\r\n" ); document.write( "\r\n" ); document.write( " X1 X2 X3 b\r\n" ); document.write( "1 1 1 1 -5\r\n" ); document.write( "2 0 1 -1 -2\r\n" ); document.write( "3 0 -3 -3 18\r\n" ); document.write( "\r\n" ); document.write( "Subtract the 2nd row from the 1st row\r\n" ); document.write( "\r\n" ); document.write( "X1 X2 X3 b\r\n" ); document.write( "1 1 0 2 -3\r\n" ); document.write( "2 0 1 -1 -2\r\n" ); document.write( "3 0 -3 -3 18\r\n" ); document.write( "\r\n" ); document.write( "Multiply the 2nd row by -3\r\n" ); document.write( "\r\n" ); document.write( " X1 X2 X3 b\r\n" ); document.write( "1 1 0 2 -3\r\n" ); document.write( "2 0 -3 3 6\r\n" ); document.write( "3 0 -3 -3 18\r\n" ); document.write( "\r\n" ); document.write( "Subtract the 2nd row from the 3rd row and restore it\r\n" ); document.write( "\r\n" ); document.write( " X1 X2 X3 b\r\n" ); document.write( "1 1 0 2 -3\r\n" ); document.write( "2 0 1 -1 -2\r\n" ); document.write( "3 0 0 -6 12\r\n" ); document.write( "\r\n" ); document.write( "Make the pivot in the 3rd column by dividing the 3rd row by -6\r\n" ); document.write( "\r\n" ); document.write( " X1 X2 X3 b\r\n" ); document.write( "1 1 0 2 -3\r\n" ); document.write( "2 0 1 -1 -2\r\n" ); document.write( "3 0 0 1 -2\r\n" ); document.write( "\r\n" ); document.write( "Multiply the 3rd row by 2\r\n" ); document.write( "\r\n" ); document.write( " X1 X2 X3 b\r\n" ); document.write( "1 1 0 2 -3\r\n" ); document.write( "2 0 1 -1 -2\r\n" ); document.write( "3 0 0 2 -4\r\n" ); document.write( "\r\n" ); document.write( "Subtract the 3rd row from the 1st row and restore it\r\n" ); document.write( "\r\n" ); document.write( " X1 X2 X3 b\r\n" ); document.write( "1 1 0 0 1\r\n" ); document.write( "2 0 1 -1 -2\r\n" ); document.write( "3 0 0 1 -2\r\n" ); document.write( "\r\n" ); document.write( "Multiply the 3rd row by -1\r\n" ); document.write( "\r\n" ); document.write( " X1 X2 X3 b\r\n" ); document.write( "1 1 0 0 1\r\n" ); document.write( "2 0 1 -1 -2\r\n" ); document.write( "3 0 0 -1 2\r\n" ); document.write( "\r\n" ); document.write( "Subtract the 3rd row from the 2nd row and restore it\r\n" ); document.write( "\r\n" ); document.write( " X1 X2 X3 b\r\n" ); document.write( "1 1 0 0 1\r\n" ); document.write( "2 0 1 0 -4\r\n" ); document.write( "3 0 0 1 -2\r\n" ); document.write( "\r\n" ); document.write( "Solution set:\r\n" ); document.write( "\r\n" ); document.write( "x1 = 1 \r\n" ); document.write( "x2 = -4 \r\n" ); document.write( "x3 = -2 \r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |