document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1131281>Question 1131281</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a square rug has an area of 91 square feet.\r<BR>\n" );
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document.write( "what is a good approximation of the perimeter of the rug? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #747907 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=747907\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if the rug is square, then the formula for the area of the rug is A = S^2.\r<BR>\n" );
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document.write( "since A = 91, then the formula becomes 91 = S^2.\r<BR>\n" );
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document.write( "solve for S to get S = sqrt(91).\r<BR>\n" );
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document.write( "the formula for the perimter of the square rug is 4S = P\r<BR>\n" );
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document.write( "since S = sqrt(91), then the formula becomes 4 * sqrt(91) = P.\r<BR>\n" );
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document.write( "the perimeter is equal to 4 * sqrt(91).\r<BR>\n" );
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document.write( "sqrt(91) is approximately equal to 9.539392014 feet.\r<BR>\n" );
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document.write( "4 * sqrt(91) is approximately equal to 38.15756806 feet.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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