document.write( "Question 102824This question is from textbook
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document.write( ": I don't know how to solve this problem - please help\r
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document.write( "Solve the system by addition method\r
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document.write( "Eq 1 states: .18x + .27y = .09
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document.write( "Eq 2 states: .06x - .54y = -.04\r
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document.write( "I'm really stuck here, and need some help \n" );
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Algebra.Com's Answer #74776 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! YOU HAVE 2 CHOICES HERE: \n" ); document.write( "YOU CAN MULTIPLY THE FIRST EQUATION BY 2 (ELIMINATE THE Y TERM OR MULTIPLY THE SECOND EQUATION BY -3 (ELIMINATES THE X TERM)& THEN ADD THEM. \n" ); document.write( ".36X+.54Y=.18 \n" ); document.write( ".06X-.54Y=-.04 NOW ADD: \n" ); document.write( "----------------------------------- \n" ); document.write( ".42X=.14 \n" ); document.write( "X=.14/.42 \n" ); document.write( "X=1/3 ANSWER. \n" ); document.write( "NOW REPLACE X BY 1/3 & SOLVE FOR Y. \n" ); document.write( ".06*1/3-.54Y=-.04 \n" ); document.write( ".02-.54Y=-.04 \n" ); document.write( "-.54Y=-.04-.02 \n" ); document.write( "-.54Y=-.06 \n" ); document.write( "Y=-.06/-.54 \n" ); document.write( "Y=1/9 ANSWER. \n" ); document.write( "PROOF \n" ); document.write( ".18*1/3+.27*1/9=.09 \n" ); document.write( ".06+.03=.09 \n" ); document.write( ".09=.09\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |