document.write( "Question 1131118: in how many ways can 10 people seated on a bench if only 5 are seats are available \n" ); document.write( "

Algebra.Com's Answer #747759 by ikleyn(52781) $\"\"$ $\"About$

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\n" ); document.write( "in how many ways can 10 people $\"highlight%28be%29\"$ seated on a bench if only 5 $\"highlight%28cross%28are%29%29\"$ seats are available
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\n" ); document.write( "\n" ); document.write( " . . . In other words, in how many ways can 5 people be selected from 10 people and ordered . . . \r
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\n" ); document.write( "\n" ); document.write( "Answer. In 10*9*8*7*6 = 30240 ways.\r
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document.write( "Any of the 10 persons can be placed on the seat #1;\r\n" );
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document.write( "any of the remaining 9 persons can be placed on the seat #2;\r\n" );
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document.write( "any of  ------------ 8 ---------------''---------------- #3;\r\n" );
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document.write( "any of  ------------ 7 ---------------''---------------- #4;\r\n" );
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document.write( "any of  ------------ 6 ---------------''---------------- #5.\r\n" );
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document.write( "The product of the numbers of these options gives the answer.\r\n" );
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\n" ); document.write( "\n" ); document.write( "You may find millions of similar problems in combinatorics, and all of them are solved in this way.\r
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