document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1131120>Question 1131120</A>: <I><SPAN STYLE=\"word-break: break-all;\"> \"Julio intends to drive his motorbike to a friend's house 200 kilometers away. If he increases his planned rate of speed by 10km/hr, he can decrease his travel time by 40 minutes. What is his planned rate of speed?\" \r<BR>\n" );
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document.write( "I made a RxT=D chart and I had an original rate and a new rate.\r<BR>\n" );
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document.write( "Original Rate | R = x - 10 | T = 200/(x-10) | D = 200\r<BR>\n" );
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document.write( "New Rate | R = x + 10 | T = 200/(x+10) | D = 200\r<BR>\n" );
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document.write( "I feel like I filled out the chart a bit off and thus resulting in solving my problem wrong. (I wasn't able to multiply & distribute all the way through so I didn't get an answer) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #747735 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=747735\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  \"Julio intends to drive his motorbike to a friend's house 200 kilometers away. If he increases his planned rate of speed by 10km/hr, he can decrease his travel time by 40 minutes. What is his planned rate of speed?\" <BR>\n" );
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document.write( "Original Data::<BR>\n" );
document.write( "rate = r kph ; time = t hrs ; distance = 200 km<BR>\n" );
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document.write( "New DATA:<BR>\n" );
document.write( "rate = r+10 kph ; time = t-(2/3) ; distance = 200 km<BR>\n" );
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document.write( "Equations:<BR>\n" );
document.write( "r*t = 200<BR>\n" );
document.write( "(r+10)(t-2/3) = 200<BR>\n" );
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document.write( "Substitute for \"t\" and solve for \"r\"<BR>\n" );
document.write( "(r+10)((200/r)-(2/3)) = 200<BR>\n" );
document.write( "(r+10)[(600-2r)/(3r)] = 200<BR>\n" );
document.write( "(r+10)(600-2r) = 600r<BR>\n" );
document.write( "600r -2r^2 + 1200 - 20r = 600r<BR>\n" );
document.write( "r^2 +20r - 1200 = 0<BR>\n" );
document.write( "r is approximately 26 kph<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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