document.write( "Question 1131120: \"Julio intends to drive his motorbike to a friend's house 200 kilometers away. If he increases his planned rate of speed by 10km/hr, he can decrease his travel time by 40 minutes. What is his planned rate of speed?\" \r
\n" ); document.write( "\n" ); document.write( "I made a RxT=D chart and I had an original rate and a new rate.\r
\n" ); document.write( "\n" ); document.write( "Original Rate | R = x - 10 | T = 200/(x-10) | D = 200\r
\n" ); document.write( "\n" ); document.write( "New Rate | R = x + 10 | T = 200/(x+10) | D = 200\r
\n" ); document.write( "\n" ); document.write( "I feel like I filled out the chart a bit off and thus resulting in solving my problem wrong. (I wasn't able to multiply & distribute all the way through so I didn't get an answer)
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Algebra.Com's Answer #747730 by josgarithmetic(39630)\"\" \"About 
You can put this solution on YOUR website!
r, the normal speed\r
\n" ); document.write( "\n" ); document.write( "r+10, the \"if increase by 10 kilometer/hour\" speed\r
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document.write( "                     SPEED       TIME       DISTANCE\r\n" );
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document.write( "Normal               r          200/r       200\r\n" );
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document.write( "If faster            r+10      200/(r+10)   200\r\n" );
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document.write( "Difference                      2/3\r\n" );
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\n" ); document.write( "\n" ); document.write( "The equation to match the time difference for 40 minutes, \"2%2F3\" of an hour,\r
\n" ); document.write( "\n" ); document.write( "\"200%2Fr-200%2F%28r%2B10%29=2%2F3\"
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