document.write( "Question 1131120: \"Julio intends to drive his motorbike to a friend's house 200 kilometers away. If he increases his planned rate of speed by 10km/hr, he can decrease his travel time by 40 minutes. What is his planned rate of speed?\" \r
\n" );
document.write( "\n" );
document.write( "I made a RxT=D chart and I had an original rate and a new rate.\r
\n" );
document.write( "\n" );
document.write( "Original Rate | R = x - 10 | T = 200/(x-10) | D = 200\r
\n" );
document.write( "\n" );
document.write( "New Rate | R = x + 10 | T = 200/(x+10) | D = 200\r
\n" );
document.write( "\n" );
document.write( "I feel like I filled out the chart a bit off and thus resulting in solving my problem wrong. (I wasn't able to multiply & distribute all the way through so I didn't get an answer) \n" );
document.write( "
Algebra.Com's Answer #747730 by josgarithmetic(39630) ![]() You can put this solution on YOUR website! r, the normal speed\r \n" ); document.write( "\n" ); document.write( "r+10, the \"if increase by 10 kilometer/hour\" speed\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( " SPEED TIME DISTANCE\r\n" ); document.write( "\r\n" ); document.write( "Normal r 200/r 200\r\n" ); document.write( "\r\n" ); document.write( "If faster r+10 200/(r+10) 200\r\n" ); document.write( "\r\n" ); document.write( "Difference 2/3\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "The equation to match the time difference for 40 minutes, \n" ); document.write( "\n" ); document.write( " |