document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1131105>Question 1131105</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In 2002 a cable company charged $34.99 per month. In 2005 it cost $43.43.<BR>\n" );
document.write( "What is the company's equation? Use C for the cost per month and t for time in years since 2002. (2003=1)<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #747718 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=747718\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In 2002 a cable company charged $34.99 per month. In 2005 it cost $43.43.<BR>\n" );
document.write( "What is the company's equation? Use C for the cost per month and t for time in years since 2002. (2003=1)<BR>\n" );
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document.write( "slope = 12(43.43-34.99)/(4-1) = 12*8.44/3 = 33.76 (amt. of cost gain per year)\r<BR>\n" );
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document.write( "intercept:: C(1 yr.) = 12*34.99 so C(0) = 12*34.99-33.76 = 386.12<BR>\n" );
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document.write( "Equation::<BR>\n" );
document.write( "C(t) = 33.76t + 386.12<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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