document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1131058>Question 1131058</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the area of the base a right circular cone is 38.50 sq. cm. if its height is three times the radius of the base find its volume </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #747677 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=747677\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the area of the base a right circular cone is 38.50 sq. cm.<BR>\n" );
document.write( "find r, the radius<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi%2Ar%5E2+=+38.5 ALIGN=MIDDLE  ALT=\"pi%2Ar%5E2+=+38.5\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "r = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%2838.5%2Fpi%29 ALIGN=MIDDLE  ALT=\"sqrt%2838.5%2Fpi%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "r = 3.5 cm<BR>\n" );
document.write( " if its height is three times the radius of the base, <BR>\n" );
document.write( "h = 3(3.5) <BR>\n" );
document.write( "h = 10.5 cm is the height<BR>\n" );
document.write( "find it's volume<BR>\n" );
document.write( "V = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F3 ALIGN=MIDDLE  ALT=\"1%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi%2A3.5%5E2%2A10.5 ALIGN=MIDDLE  ALT=\"pi%2A3.5%5E2%2A10.5\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "V = 134.7 cu/cm is the volume<BR>\n" );
document.write( ":<BR>\n" );
document.write( "The area of a cone:<BR>\n" );
document.write( "Find the slant height of the cone<BR>\n" );
document.write( "s = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%283.5%5E2%2B10.5%5E2%29 ALIGN=MIDDLE  ALT=\"sqrt%283.5%5E2%2B10.5%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "s = 11.07 cm is the slant height<BR>\n" );
document.write( "Find the lateral area A = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi%2Ar%2As ALIGN=MIDDLE  ALT=\"pi%2Ar%2As\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "A = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi%2A3.5%2A11.07 ALIGN=MIDDLE  ALT=\"pi%2A3.5%2A11.07\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "A = 121.7 sq/cm is the lateral surface area<BR>\n" );
document.write( ":<BR>\n" );
document.write( "If you want the total surface area, add 38.5 to the later surface area<BR>\n" );
document.write( "   </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );