document.write( "Question 1131041: The sum of three numbers is 77. The sum of twice the first number, 55 times the second number, and 66 times the third number is 2525. The difference between 88 times the first number and the second number is 3131. Find the three numbers. \n" ); document.write( "
Algebra.Com's Answer #747657 by josgarithmetic(39616)![]() ![]() ![]() You can put this solution on YOUR website! Are you typing in mistakes on purpose, or are those values actually how your given exercise states them? \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Assuming the first, second, third numbers are x, y, z, and you did not really mean the doubled digits given, then\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solve the system however you want. \n" ); document.write( " |