document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1131032>Question 1131032</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A boat can travel 24 miles downstream in 2 hrs. The return trip takes 3 hrs. Find the speed of the boat in still water. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #747627 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=747627\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  A boat can travel 24 miles downstream in 2 hrs. The return trip takes 3 hrs. Find the speed of the boat in still water.<BR>\n" );
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document.write( "Downstream rate = 24 miles/2 hrs = 12 mph<BR>\n" );
document.write( "Upstream rate = 24 miles/3 hrs = 8 mph<BR>\n" );
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document.write( "Let\" \"b\" be the speed of the boat in still water; Let \"c\" be the current rate.<BR>\n" );
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document.write( "Equations:<BR>\n" );
document.write( "b + c = 12 mph<BR>\n" );
document.write( "b - c = 8 mph<BR>\n" );
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document.write( "2b = 20 mph<BR>\n" );
document.write( "b = 10 mph (boat speed in still water)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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