document.write( "Question 1130991: a 70% acid is to be mixed with water to produce a 5 liter mixture containing 28% acid. How many milliliters of water and how many milliliters of the 70% acid solution are needed to create the 28% acid solution? \n" ); document.write( "

Algebra.Com's Answer #747595 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"+a+\"$ = liters of 70% mixture needed
\n" ); document.write( "Let $\"+b+\"$ = liters of water needed
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\n" ); document.write( "(1) $\"+a+%2B+b+=+5+\"$ liters
\n" ); document.write( "(2) $\"+.7a+%2F+5+=+.28+\"$
\n" ); document.write( "---------------------------------
\n" ); document.write( "(2) $\"+.7a+=+1.4+\"$
\n" ); document.write( "(2) $\"+a+=+2+\"$ liters
\n" ); document.write( "and
\n" ); document.write( "(1) $\"+2+%2B+b+=+5+\"$
\n" ); document.write( "(1) $\"+b+=+3+\"$ liters
\n" ); document.write( "------------------------
\n" ); document.write( "3,000 ml of water and 2,000 ml of 70% mixture are needed
\n" ); document.write( " \n" ); document.write( "

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