document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1130944>Question 1130944</A>: <I><SPAN STYLE=\"word-break: break-all;\"> kevin and randy have a jar containing 69 coins all of which are either quarters or nickels the total value of the coins is $9.25 how many of each type of coin is there ?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #747568 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13203)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=747568\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Here is a quick way to solve this kind of problem if a formal algebraic solution is not required.<br><BR>\n" );
document.write( "(1) If all 69 coins were quarters, the value would be $3.45.  The actual value is $9.25, which is $5.80 more than $3.45.<BR>\n" );
document.write( "(2) Exchanging a nickel for a quarter keeps the number of coins at 69 but increases the total value by 20 cents.<BR>\n" );
document.write( "(3) The number of nickels that need to be exchanged for quarters to make the additional $5.80 is $5.80/$0.20 = 29.<br><BR>\n" );
document.write( "So there are 29 quarters, which leaves 69-29 = 40 nickels. </SPAN>\n" );
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