document.write( "Question 1130716: (M ∨ R) ⊃ ∼K
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document.write( "(G ⊃ ∼K) ⊃ C
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document.write( "G ⊃ (M ∨ R) /C \n" );
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Algebra.Com's Answer #747534 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( "1. (M or R) -> ~K\r\n" ); document.write( "2. (G -> ~K) -> C\r\n" ); document.write( "3. G -> (M or R) | C\r\n" ); document.write( "\r\n" ); document.write( " 4. Assume ~C \r\n" ); document.write( " 5. ~(G -> ~K) 2,4 Modus Tollens\r\n" ); document.write( " 6. G and K 5 Definition of Implication\r\n" ); document.write( " 7. G 6 Simplification\r\n" ); document.write( " 8. K 6 Simplification\r\n" ); document.write( " 9. ~(M or R) 1,7 Modus Tollens\r\n" ); document.write( " 10. ~G 3,9 Modus Tollens\r\n" ); document.write( "11. ~C -> (G and ~G) 4,7,10\r\n" ); document.write( "12. Therefore C 11 Tertium non datur\r\n" ); document.write( " \r\n" ); document.write( " \n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " ![]() \n" ); document.write( " |