document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1130878>Question 1130878</A>: <I><SPAN STYLE=\"word-break: break-all;\">  One hose can fill a goldfish pond and 91 minutes, and two hoses confer the same pond in 42 minutes. Find how long it takes a second hose alone to fill the pond </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #747498 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=747498\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> One hose: 1/91<BR>\n" );
document.write( "Second hose: We don't know, call it x: 1/x<BR>\n" );
document.write( "Both hoses: 1/42<BR>\n" );
document.write( "So now we have:<BR>\n" );
document.write( "1/91 + 1/x = 1/42<BR>\n" );
document.write( "(x + 91)/(91 * x) = 1/42<BR>\n" );
document.write( "42(x + 91) = 91x<BR>\n" );
document.write( "42x + 42 * 91x<BR>\n" );
document.write( "42x + 3822 = 91x<BR>\n" );
document.write( "42x + 3822 - 91x = 0<BR>\n" );
document.write( "-49x + 3822 = 0<BR>\n" );
document.write( "-49x = -3822<BR>\n" );
document.write( "x = 78<BR>\n" );
document.write( "It takes the 2nd hose alone 78 minutes to fill the pond </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );