document.write( "Question 1130860: Math 9 theorem 3: the diagonals of a rhombus is perpendicular
\n" ); document.write( "Proof!!
\n" ); document.write( "Plss help me to answer the proof
\n" ); document.write( "

Algebra.Com's Answer #747478 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
\"Image\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "proof: the diagonals are perpendicular to each other\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " assuming we have a rhombus \"ABCD\" with diagonals \"AC\" and \"BD\" intersecting at point \"E\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"AE\"\"CE\"..................as two halves of a diagonal \"AC\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"BE\"\"BE\"................. by reflexive property of congruence, a segment is congruent to itself \r
\n" ); document.write( "\n" ); document.write( "\"AB\"\"CB\".....................as sides of a rhombus\r
\n" ); document.write( "\n" ); document.write( "Δ \"+AEB+\" ≅ Δ \"CEB\"..........by SSS congruence
\n" ); document.write( "< \"AEB\" ≅ < \"CEB\"....................... corresponding angles
\n" ); document.write( "< \"AEB\" + < \"CEB\"=\"180\"°.........since they are supplementary angles
\n" ); document.write( "< \"AEB\" = < \"CEB\"=\"90\"°..........addition property of congruent angles\r
\n" ); document.write( "\n" ); document.write( "\"AC\"\"BD\"..........the diagonals of \"ABCD\" are perpendicular to each other\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );