document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1130862>Question 1130862</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The measure of two sides of a triangle are given.  Between what two numbers must the third fall? Complete the inequality.\r<BR>\n" );
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document.write( "11 and 20 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #747477 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=747477\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The sum of any two sides has to be greater than the third.<BR>\n" );
document.write( "so 11+20=31> side 3 or side 3 < 31<BR>\n" );
document.write( "let side 3 be x<BR>\n" );
document.write( "x+11>20, so x>9<BR>\n" );
document.write( "x+20>11 always<BR>\n" );
document.write( "So 9 <x< 31 </SPAN>\n" );
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