document.write( "Question 1130815: Find the angle theta (in radians) that maximizes the area of the isosceles triangle whose legs have length = 7,using the fact that the area is given by
\n" ); document.write( "A = 1/2l^2sin(theta).
\n" ); document.write( "

Algebra.Com's Answer #747472 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "Although not clearly stated in the problem, theta is the angle between the two sides of length 7.

\n" ); document.write( "If you need to use the formula \"A+=+%281%2F2%29%287%5E2%29sin%28theta%29\" to solve the problem, then consider one of the legs of length 7 as the base; then the height of the triangle is the length of the other leg of length 7, multiplied by sin(theta). So clearly the area is maximum when sin(theta) is maximum -- which is at 90 degrees.

\n" ); document.write( "You don't really need the formal mathematical formula to find that result. With one of the legs of length 7 the base, the height of the triangle is the distance from the end of the other leg of length 7 to the base; obviously that distance is the greatest when the angle is 90 degrees.
\n" ); document.write( "
\n" );