document.write( "Question 102775This question is from textbook
\n" ); document.write( ": Please help me with this problem\r
\n" ); document.write( "\n" ); document.write( "Eq 1 states: 3x = 3 + 2y
\n" ); document.write( "E1 2 states: -4/3x + y = 1/3\r
\n" ); document.write( "\n" ); document.write( "I'm really confused and need some help.\r
\n" ); document.write( "\n" ); document.write( "Thanks
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Algebra.Com's Answer #74747 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Eq 1 states: 3x = 3 + 2y
\n" ); document.write( "E1 2 states: (-4/3)x + y = 1/3\r
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\n" ); document.write( "Rewrite the equations:
\n" ); document.write( "Eq 1 : 3x -2y = 3
\n" ); document.write( "Eq 2 :-4x +3y = 1
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\n" ); document.write( "Multiply Eq 1 by 3 and Eq 2 by 2 to get:
\n" ); document.write( "Eq 3: 9x -6y = 9
\n" ); document.write( "Eq 2:-8x +6y = 2
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\n" ); document.write( "Add the wo equations to get:
\n" ); document.write( "x = 11
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\n" ); document.write( "Substitute into Eq 1 to solve for y:
\n" ); document.write( "3*11 = 3 + 2y
\n" ); document.write( "30 = 2y
\n" ); document.write( "y = 15
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\n" ); document.write( "Solution : x=11, y=15
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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