document.write( "Question 102775This question is from textbook
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document.write( ": Please help me with this problem\r
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document.write( "Eq 1 states: 3x = 3 + 2y
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document.write( "E1 2 states: -4/3x + y = 1/3\r
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document.write( "I'm really confused and need some help.\r
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document.write( "Thanks \n" );
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Algebra.Com's Answer #74747 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Eq 1 states: 3x = 3 + 2y \n" ); document.write( "E1 2 states: (-4/3)x + y = 1/3\r \n" ); document.write( "\n" ); document.write( "------------------- \n" ); document.write( "Rewrite the equations: \n" ); document.write( "Eq 1 : 3x -2y = 3 \n" ); document.write( "Eq 2 :-4x +3y = 1 \n" ); document.write( "---------------- \n" ); document.write( "Multiply Eq 1 by 3 and Eq 2 by 2 to get: \n" ); document.write( "Eq 3: 9x -6y = 9 \n" ); document.write( "Eq 2:-8x +6y = 2 \n" ); document.write( "------------------ \n" ); document.write( "Add the wo equations to get: \n" ); document.write( "x = 11 \n" ); document.write( "---------- \n" ); document.write( "Substitute into Eq 1 to solve for y: \n" ); document.write( "3*11 = 3 + 2y \n" ); document.write( "30 = 2y \n" ); document.write( "y = 15 \n" ); document.write( "--------------- \n" ); document.write( "Solution : x=11, y=15 \n" ); document.write( "================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |