document.write( "Question 1130815: Find the angle theta (in radians) that maximizes the area of the isosceles triangle whose legs have length = 7,using the fact that the area is given by
\n" ); document.write( "A = 1/2l^2sin(theta).
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Algebra.Com's Answer #747457 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "You mean where is the length of one of the equal sides of the isosceles triangle and is the vertex angle.\r
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\n" ); document.write( "\n" ); document.write( "Any single angle of any triangle must be in the range . The maximum value for the sine function in this range is 1 when . Since is independent of the measure of the vertex angle, the maximum area must occur where is maximum.\r
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\n" ); document.write( "\n" ); document.write( "Or you can use the Calculus:\r
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\n" ); document.write( "\n" ); document.write( "Therefore is a local extremum of the function\r
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\n" ); document.write( "\n" ); document.write( "Which is a negative value when , therefore is a local maximum of the area function.
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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