document.write( "Question 102756This question is from textbook
\n" ); document.write( ": Please help with the following problem:\r
\n" ); document.write( "\n" ); document.write( "Solve the system by addition method:\r
\n" ); document.write( "\n" ); document.write( "Eq 1 states 3x + 3y = 33
\n" ); document.write( "Eq 2 states 5x - 2y = 27\r
\n" ); document.write( "\n" ); document.write( "Please show work.\r
\n" ); document.write( "\n" ); document.write( "Thank you
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #74745 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: Solving a System of Linear Equations by Elimination/Addition

\n" ); document.write( "
\n" ); document.write( " Lets start with the given system of linear equations
\n" ); document.write( "
\n" ); document.write( " \"3%2Ax%2B3%2Ay=33\"
\n" ); document.write( " \"5%2Ax-2%2Ay=27\"
\n" ); document.write( "
\n" ); document.write( " In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for y, we would have to eliminate x (or vice versa).
\n" ); document.write( "
\n" ); document.write( " So lets eliminate x. In order to do that, we need to have both x coefficients that are equal but have opposite signs (for instance 2 and -2 are equal but have opposite signs). This way they will add to zero.
\n" ); document.write( "
\n" ); document.write( " So to make the x coefficients equal but opposite, we need to multiply both x coefficients by some number to get them to an equal number. So if we wanted to get 3 and 5 to some equal number, we could try to get them to the LCM.
\n" ); document.write( "
\n" ); document.write( " Since the LCM of 3 and 5 is 15, we need to multiply both sides of the top equation by 5 and multiply both sides of the bottom equation by -3 like this:
\n" ); document.write( "
\n" ); document.write( " \"5%2A%283%2Ax%2B3%2Ay%29=%2833%29%2A5\" Multiply the top equation (both sides) by 5
\n" ); document.write( " \"-3%2A%285%2Ax-2%2Ay%29=%2827%29%2A-3\" Multiply the bottom equation (both sides) by -3
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So after multiplying we get this:
\n" ); document.write( " \"15%2Ax%2B15%2Ay=165\"
\n" ); document.write( " \"-15%2Ax%2B6%2Ay=-81\"
\n" ); document.write( "
\n" ); document.write( " Notice how 15 and -15 add to zero (ie \"15%2B-15=0\")
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Now add the equations together. In order to add 2 equations, group like terms and combine them
\n" ); document.write( " \"%2815%2Ax-15%2Ax%29%2B%2815%2Ay%2B6%2Ay%29=165-81\"
\n" ); document.write( "
\n" ); document.write( " \"%2815-15%29%2Ax%2B%2815%2B6%29y=165-81\"
\n" ); document.write( "
\n" ); document.write( " \"cross%2815%2B-15%29%2Ax%2B%2815%2B6%29%2Ay=165-81\" Notice the x coefficients add to zero and cancel out. This means we've eliminated x altogether.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So after adding and canceling out the x terms we're left with:
\n" ); document.write( "
\n" ); document.write( " \"21%2Ay=84\"
\n" ); document.write( "
\n" ); document.write( " \"y=84%2F21\" Divide both sides by \"21\" to solve for y
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"y=4\" Reduce
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Now plug this answer into the top equation \"3%2Ax%2B3%2Ay=33\" to solve for x
\n" ); document.write( "
\n" ); document.write( " \"3%2Ax%2B3%284%29=33\" Plug in \"y=4\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"3%2Ax%2B12=33\" Multiply
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"3%2Ax=33-12\" Subtract \"12\" from both sides
\n" ); document.write( "
\n" ); document.write( " \"3%2Ax=21\" Combine the terms on the right side
\n" ); document.write( "
\n" ); document.write( " \"cross%28%281%2F3%29%283%29%29%2Ax=%2821%29%281%2F3%29\" Multiply both sides by \"1%2F3\". This will cancel out \"3\" on the left side.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"x=7\" Multiply the terms on the right side
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So our answer is
\n" ); document.write( "
\n" ); document.write( " \"x=7\", \"y=4\"
\n" ); document.write( "
\n" ); document.write( " which also looks like
\n" ); document.write( "
\n" ); document.write( " (\"7\", \"4\")
\n" ); document.write( "
\n" ); document.write( " Notice if we graph the equations (if you need help with graphing, check out this solver)
\n" ); document.write( "
\n" ); document.write( " \"3%2Ax%2B3%2Ay=33\"
\n" ); document.write( " \"5%2Ax-2%2Ay=27\"
\n" ); document.write( "
\n" ); document.write( " we get
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " graph of \"3%2Ax%2B3%2Ay=33\" (red) \"5%2Ax-2%2Ay=27\" (green) (hint: you may have to solve for y to graph these) and the intersection of the lines (blue circle).
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " and we can see that the two equations intersect at (\"7\",\"4\"). This verifies our answer.
\n" ); document.write( "
\n" ); document.write( "
\n" );