document.write( "Question 1130823: A motorboat takes 5 hours to travel 100 km going upstream. The return trip takes 2 hours going downstream. What is the rate of the boat in still water and what is the rate of the current? \r
\n" ); document.write( "\n" ); document.write( "Rate of the boat in still water:\r
\n" ); document.write( "\n" ); document.write( "Rate of the current:
\n" ); document.write( "

Algebra.Com's Answer #747442 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
let \"s+\" = the speed of the boat in still water in km/hr
\n" ); document.write( "Let \"+w+\" = the speed of the current in km/hr
\n" ); document.write( "Going upstream:
\n" ); document.write( "(1) \"+100+=+%28+s+-+w+%29%2A5+\"
\n" ); document.write( "Going downstream:
\n" ); document.write( "(2) \"+100+=+%28+s+%2B+w+%29%2A2+\"
\n" ); document.write( "-------------------------------
\n" ); document.write( "(1) \"+5s+-+5w+=+100+\"
\n" ); document.write( "(2) \"+2s+%2B+2w+=+100+\"
\n" ); document.write( "Multiply (1) by \"2+\", multiply
\n" ); document.write( "(2) by \"+5+\", and add the equations
\n" ); document.write( "-----------------------------------------------
\n" ); document.write( "(2) \"+10s+%2B+10w+=+500+\"
\n" ); document.write( "(1) \"+10s+-+10w+=+200+\"
\n" ); document.write( "-------------------------------
\n" ); document.write( "\"+20s+=+700+\"
\n" ); document.write( "\"+s+=+35+\"
\n" ); document.write( "and
\n" ); document.write( "(2) \"+2%2A35+%2B+2%2Aw+=+100+\"
\n" ); document.write( "(2) \"+2w+=+30+\"
\n" ); document.write( "(2) \"+w+=+15+\"
\n" ); document.write( "-----------------------------
\n" ); document.write( "Rate in still water: 35 km/hr
\n" ); document.write( "Rate of the current: 15 km/hr\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );