document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=102719>Question 102719</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The hypotenuse of a right triangle is 20 centimeters. The sum of the other two sides is 28 centimeters. Find the length of two sides. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #74742 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=74742\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a+b=28<BR>\n" );
document.write( "let b=28-a<BR>\n" );
document.write( "a^2+(28-a)^2=20^2<BR>\n" );
document.write( "a^2+a^2-56a+784=400<BR>\n" );
document.write( "2a^2-56a+384=0<BR>\n" );
document.write( "2(a^2-28+192)=0<BR>\n" );
document.write( "2(a-12)(a-16)=0<BR>\n" );
document.write( "a=12, a=16<BR>\n" );
document.write( "So the 2 sides are 12 cm and 16 cm<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );