document.write( "Question 1130793: Use two equations in two variables to solve the application. \r
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document.write( "A rancher raises three times as many cows as horses. If he has 112 animals, how many cows does he have?
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Algebra.Com's Answer #747402 by ikleyn(52799)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( "Let C be the number of cows and H be the number of horses.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "From the condition, you have this system of 2 equations in 2 unknowns\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "C = 3H, (1)\r\n" ); document.write( "C + H = 112. (2)\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Solve it by the substitution method.\r\n" ); document.write( "From equation (1), you just have an expression for C. Substitute it into equation (2), replacing C:\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "3H + H = 112,\r\n" ); document.write( "\r\n" ); document.write( "4H = 112\r\n" ); document.write( "\r\n" ); document.write( "H = 112/4 = 28.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Answer. 28 horses and 3*28 = 84 cows.\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |