document.write( "Question 102709This question is from textbook Algebra
\n" ); document.write( ": My question is:\r
\n" ); document.write( "\n" ); document.write( "Jo has 37 coins (all nickels, dimes, and quarters) worth $5.50. She has 4 more quarters than nickels. How many dimes does Jo have?\r
\n" ); document.write( "\n" ); document.write( "I am supposed to figure out how many dimes she has and I have to figure out my equations with a chart to help me. So far I have concluded that: \r
\n" ); document.write( "\n" ); document.write( "1.) Number of Coins x Value of coins = Total value ($5.50) is the equation\r
\n" ); document.write( "\n" ); document.write( "2.) Nickels-- .05N\r
\n" ); document.write( "\n" ); document.write( "3.) Dimes-- (37-N).10\r
\n" ); document.write( "\n" ); document.write( "4.) Quarters-- (4+N).25\r
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Algebra.Com's Answer #74734 by scott8148(6628)\"\" \"About 
You can put this solution on YOUR website!
your expressions look OK except for the dimes ... you subtracted the nickels from the total but not the quarters\r
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\n" ); document.write( "\n" ); document.write( "try Dimes-- (37-N-(N+4)).10\r
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\n" ); document.write( "\n" ); document.write( "the three expressions summed together equal the total value
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