document.write( "Question 1130604: Solve the system of equations. (If the system is dependent, enter a general solution in terms of c
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document.write( "{2x− y+ z = 12
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document.write( " 2y− 3z= −16
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document.write( " 3y + 2z= 2
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document.write( "(x, y, z) = \n" );
document.write( "
Algebra.Com's Answer #747316 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Solve the system of equations. (If the system is dependent, enter a general solution in terms of c \n" ); document.write( "2x− y+ z = 12 \n" ); document.write( "2y − 3z = −16 \n" ); document.write( "3y + 2z = 2 \n" ); document.write( "(x, y, z) = \n" ); document.write( ": \n" ); document.write( "Let's just deal with the last two equations \n" ); document.write( "2y - 3z = -16 \n" ); document.write( "3y + 2z = 2 \n" ); document.write( "Use elimination, multiply the 1st eq by 2, the 2nd eq by 3 \n" ); document.write( "4y - 6z = -32 \n" ); document.write( "9y + 6z = 6 \n" ); document.write( "--------------addition eliminates z, find y \n" ); document.write( "13y = -26 \n" ); document.write( "y = -26/13 \n" ); document.write( "y = -2 \n" ); document.write( "Find z using the 3rd equation \n" ); document.write( "3(-2) + 2z = 2 \n" ); document.write( "-6 + 2z = 2 \n" ); document.write( "2z = 2 + 6 \n" ); document.write( "2z = 8 \n" ); document.write( "z = 8/2 \n" ); document.write( "z = 4 \n" ); document.write( "Find x using first original equation \n" ); document.write( "2x - y + z = 12 \n" ); document.write( "y=-2, z=4 \n" ); document.write( "2x - (-2) + 4 = 12 \n" ); document.write( "2x + 2 + 4 = 12 \n" ); document.write( "2x = 12 - 6 \n" ); document.write( "2x = 6 \n" ); document.write( "x = 3 \n" ); document.write( "therefore we have x=3, y=-2, z= 4 \n" ); document.write( " |