document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1130667>Question 1130667</A>: <I><SPAN STYLE=\"word-break: break-all;\"> six years ago a man was four times as old as his son was then. in twelve years, the many will be just twice as old as his son will be then. Find their present ages. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #747287 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=747287\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> son is x now<BR>\n" );
document.write( "x-6 was his age 6 years ago<BR>\n" );
document.write( "Man's age 6 years ago was 4(x-6) or 4x-24.  That means the man is 4x-18 years old now.<BR>\n" );
document.write( "In 12 years, the man will be 4x-6 years old and that is twice as old as his son in 12 years, which is x+12<BR>\n" );
document.write( "so 4x-6=2(x+12)<BR>\n" );
document.write( "4x-6=2x+24<BR>\n" );
document.write( "2x=30<BR>\n" );
document.write( "x=15<BR>\n" );
document.write( "son is 15 now and when he was 9, his man was 36 so <BR>\n" );
document.write( "man is 42 now<BR>\n" );
document.write( "15 and 42 ANSWER<BR>\n" );
document.write( "check<BR>\n" );
document.write( "in 12 years, the man will be 54 and the son 27, which is twice as old. </SPAN>\n" );
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