document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1130638>Question 1130638</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An ordinary (fair) die is a cube with the numbers  through  on the sides (represented by painted spots). Imagine that such a die is rolled twice in succession and that the face values of the two rolls are added together. This sum is recorded as the outcome of a single trial of a random experiment.   \r<BR>\n" );
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document.write( "the probability of each of the following events:<BR>\n" );
document.write( "A: a sum greater than 5<BR>\n" );
document.write( "B: The sum is divisible by 5 or 6 (or both) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #747269 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=747269\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> sum equal to 6 has probability (5/36)<BR>\n" );
document.write( "7--1/6 or 6/36<BR>\n" );
document.write( "8--5/36<BR>\n" );
document.write( "9--4/36<BR>\n" );
document.write( "10--3/36<BR>\n" );
document.write( "11--2/36<BR>\n" );
document.write( "12--1/36<BR>\n" );
document.write( "answer to a is 26/36 or 13/18<BR>\n" );
document.write( "divisible by 5 includes 5 and 10.  This probability is 4/36 and 3/36<BR>\n" );
document.write( "by 6 includes 6 and 12 with probability 5/36 and 1/36.  Those probabilities are 13/36 when all added. </SPAN>\n" );
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