document.write( "Question 102739: Please someone help me i am lost as to howto do this.
\n" ); document.write( "Identify the axis of symmetry, create a suitable table of values, then sketch the graph including the axis of symmetry. \"y=x%5E2%2B2\"
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Algebra.Com's Answer #74726 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
First, to \"create a suitable table of values\" simply means to assign a value to the indepedent variable (that's x) and, using the given equation, find the coressponding value of the dependent variable (that's y) and make a table of these.
\n" ); document.write( "You don't say how many entries are required but 4 or 5 should suffice. Be sure to include value of x that show where the parabola intersect the x-axis, if this is applicable. (this will be true when y = 0)
\n" ); document.write( "To see if there are any x-intersects, set y = o and solve for x.
\n" ); document.write( "\"y+=+x%5E2%2B2\" Set y = 0
\n" ); document.write( "\"0+=+x%5E2%2B2\" Subtract 2 from both sides.
\n" ); document.write( "\"-2+=+x%5E2\" Take the square root of both sides.
\n" ); document.write( "\"x+=+sqrt%28-2%29\" or \"x+=+-sqrt%28-2%29\" As you can see, the x's are imaginary values \"x+=+sqrt%282%29i\" or \"x+=+-sqrt%282%29i\" so the parabola does not intersect the x-axis.
\n" ); document.write( "Here are a few values for the table.
\n" ); document.write( "x..(x^2+2)
\n" ); document.write( "0....2
\n" ); document.write( "1....3
\n" ); document.write( "2....6
\n" ); document.write( "3...11
\n" ); document.write( "4...18
\n" ); document.write( "Heres what the graph looks like:
\n" ); document.write( "\"graph%28600%2C400%2C-6%2C6%2C-4%2C25%2Cx%5E2%2B2%29\"
\n" ); document.write( "You can see the axis of symmetry on the graph...it's x = 0
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