document.write( "Question 102737: Could someone please show me how to solve its expression???
\n" ); document.write( "Solve by completing the square. \"x%5E2=5x=2\"
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Algebra.Com's Answer #74721 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Solve this equation (this is not an expression!) by completing the square:
\n" ); document.write( "\"x%5E2%2B5x+=+2\" Add the square of half the x-coefficient to both sides. This would be \"%285%2F2%29%5E2+=+25%2F4\"
\n" ); document.write( "\"x%5E2%2B5x%2Bhighlight%2825%2F4%29+=+2%2Bhighlight%2825%2F4%29\"Simplify.
\n" ); document.write( "\"x%5E2%2B5x%2B25%2F4+=+%288%2B25%29%2F4\"
\n" ); document.write( "\"x%5E2%2B5x%2B25%2F4+=+33%2F4\" Now factor the left side.
\n" ); document.write( "\"%28x%2B5%2F2%29%28x%2B5%2F2%29+=+33%2F4\" Rewrite this as:
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\n" ); document.write( "\"%28x%2B5%2F2%29%5E2+=+33%2F4\" Now take the square root of both sides.
\n" ); document.write( "\"sqrt%28%28x%2B5%2F2%29%5E2%29+=+sqrt%2833%2F4%29\" Simplify.
\n" ); document.write( "\"x%2B5%2F2+=+sqrt%2833%29%2F2\" or \"x%2B5%2F2+=+-sqrt%2833%29%2F2\" Finally, subtract \"5%2F2\" from both sides of each solution.
\n" ); document.write( "\"x+=+sqrt%2833%2F2%29-5%2F2\" or \"x+=+-sqrt%2833%29%2F2-5%2F2\" The can be written:
\n" ); document.write( "\"x+=+-%28%285-sqrt%2833%29%29%2F2%29\" or \"x+=+-%28%285%2Bsqrt%2833%29%29%2F2%29\"
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