document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1130510>Question 1130510</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Break-downs occur on an old car with a rate of 6 break-downs every four weeks. The owner of the car is planning to have a trip on his car for 4 days. What is the probability that he will return home without experiencing a car break-down?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #747188 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=747188\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> That is 6 per 28 days, so that would be 6/7 per four days, dividing both by 7.<BR>\n" );
document.write( "parameter is 6/7<BR>\n" );
document.write( "probability of 0 is e^(-6/7)=0.4244 </SPAN>\n" );
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