document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=102651>Question 102651</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A 6-quarts radiator contains a 20% antifreeze solution. How much of the solution needs to be drained out and replaced with pure antifreeze in order to raise the solution to 60% antifreeze? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #74711 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=74711\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Tricky question.<BR>\n" );
document.write( "We have to figure out what mixture of pure antifreeze must be mixed with 20% antifreeze to give a 60% soln.<BR>\n" );
document.write( "let x be the amount of 20% (.2) soln and 6-x be the amount of 100% (1) antifreeze.<BR>\n" );
document.write( "In 6 quarts of 60% antifreeze is 3.6 quarts of pure antifreeze.<BR>\n" );
document.write( ".2x+6-x=3.6<BR>\n" );
document.write( "-.8x+6=3.6<BR>\n" );
document.write( "-.8x=-2.4<BR>\n" );
document.write( "x=3<BR>\n" );
document.write( "So 3 quarts need to be drained out and replaced with 3 quarts of 100% antifreeze.<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );