document.write( "Question 1130401: (cos2x+sin2x)^2=1+sin4x \n" ); document.write( "
Algebra.Com's Answer #747075 by ikleyn(52833)\"\" \"About 
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document.write( "\"cos%282x%29+%2B+sin%282x%29%29%5E2\" = \"cos%5E2%282x%29+%2B+2%2Acos%282x%29%2Asin%282x%29+%2B+sin%5E2%282x%29\" = \"%28cos%5E2%282x%29+%2B+sin%5E2%282x%29%29\" + \"2%2Acos%282x%29%2Asin%282x%29\" = 1 + 4*sin(2x).\r\n" );
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