document.write( "Question 1130390: A man is 24 older than his son.Eight years ago, he was twice as old as his son. Calculate the present age the father and son \n" ); document.write( "
Algebra.Com's Answer #747055 by math_helper(2461)![]() ![]() You can put this solution on YOUR website! M = man's age \n" ); document.write( "S = son's age \n" ); document.write( " \r\n" ); document.write( "M = S+24 (1)\r\n" ); document.write( "M-8 = 2(S-8) (2)\r\n" ); document.write( " \r \n" ); document.write( "\n" ); document.write( "Substituting RHS of (1) into LHS of (2): \n" ); document.write( "(S+24)-8 = 2(S-8) \n" ); document.write( "Solve for S: S=32 --> M=56\r \n" ); document.write( "\n" ); document.write( "-- \n" ); document.write( "Ans: The man is 56 years old, and the son is 32 years old \n" ); document.write( "--\r \n" ); document.write( "\n" ); document.write( "Check: 56 = 32+24 ✓ \n" ); document.write( " 56 - 8 = 48 and 2(32-8) = 2(24) = 48 ✓\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |