document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1130364>Question 1130364</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve for x:\r<BR>\n" );
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document.write( "log5 x + log5(x-24) = 2\r<BR>\n" );
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document.write( "Please show me how you got the answer, thanks. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #747052 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13215)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=747052\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log%285%2Cx%29+%2B+log%285%2C%28x-24%29%29+=+2 ALIGN=MIDDLE  ALT=\"log%285%2Cx%29+%2B+log%285%2C%28x-24%29%29+=+2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br><BR>\n" );
document.write( "You have two valid and correct solutions to your equation from other tutors; let me suggest a different method that I personally find easier.<br><BR>\n" );
document.write( "My preferred first step, given two terms with log base 5 on the left and an integer on the right, is to rewrite the integer as a term in log base 5:<br><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log%285%2Cx%29+%2B+log%285%2C%28x-24%29%29+=+log%285%2C25%29 ALIGN=MIDDLE  ALT=\"log%285%2Cx%29+%2B+log%285%2C%28x-24%29%29+=+log%285%2C25%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br><BR>\n" );
document.write( "Now, with all terms log base 5, I can convert this to an ordinary algebraic equation using basic rules of logarithms; then solve the equation:<br><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%28x-24%29+=+25 ALIGN=MIDDLE  ALT=\"x%28x-24%29+=+25\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2-24x-25+=+0 ALIGN=MIDDLE  ALT=\"x%5E2-24x-25+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x-25%29%28x%2B1%29+=+0 ALIGN=MIDDLE  ALT=\"%28x-25%29%28x%2B1%29+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+25 ALIGN=MIDDLE  ALT=\"x+=+25\"   DISABLED_style= \"max-width:90%; height:auto;\" > or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+-1 ALIGN=MIDDLE  ALT=\"x+=+-1\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br><BR>\n" );
document.write( "However, the log of a negative number is not a real number, so the only solution is x = 25. </SPAN>\n" );
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