document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=102687>Question 102687</A>: <I><SPAN STYLE=\"word-break: break-all;\"> There is a rectangle whose perimeter is 46 meters and whose area is 112 square meters. What are it's dimensions???\r<BR>\n" );
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document.write( "Help!!! How could I answer this?? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #74705 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=74705\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A) 2L+2W=46<BR>\n" );
document.write( "B) L*W=112<BR>\n" );
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document.write( "W=112/L<BR>\n" );
document.write( "2L+2(112/L)=46 Substitute 112/L for W in A).<BR>\n" );
document.write( "2L+224/L=46<BR>\n" );
document.write( "2L^2+224=46L Multiply both sides by L to get rid of the fraction.<BR>\n" );
document.write( "2L^2-46L+224=0<BR>\n" );
document.write( "2(L^2-23L+112)=0<BR>\n" );
document.write( "2(L-16)(L-7)=0<BR>\n" );
document.write( "L=16, L=7<BR>\n" );
document.write( "actually we can make L=16 and W=7 or vice versa.<BR>\n" );
document.write( "Check:<BR>\n" );
document.write( "16*7=112<BR>\n" );
document.write( "2*16+2*7=46<BR>\n" );
document.write( "Ed<BR>\n" );
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