document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1130343>Question 1130343</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A principal of $1400 is invested at 6% interest, compounded annually. How many years will it take to accumulate $2000 or more in the account?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #747045 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=747045\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1400(1+0.06)^t >= 2000<BR>\n" );
document.write( "1.06^t = 1.43<BR>\n" );
document.write( "log 1.43 = t(log 1.06<BR>\n" );
document.write( "(log 1.43)/(log 1.06) = t = 6.14<BR>\n" );
document.write( "It will take approximately 6 years for the account to go frem 1400 to 2000<BR>\n" );
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