document.write( "Question 1130362: The ages of three children in a family can be expressed as consecutive integers. The square of the age of the youngest child is 4 more than 8 times the age of the oldest child. Find the ages of the three children \n" ); document.write( "
Algebra.Com's Answer #747027 by addingup(3677)\"\" \"About 
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youngest: x
\n" ); document.write( "middle : x+1
\n" ); document.write( "oldest: x+2
\n" ); document.write( "x^2 = 8(x+2)+4
\n" ); document.write( "x^2 = 8x + 16 + 4
\n" ); document.write( "x^2 = 8x + 20
\n" ); document.write( "x^2 - 8x = 20
\n" ); document.write( "x^2 - 8x - 20 = 0
\n" ); document.write( "(x−10)(x+2)=0
\n" ); document.write( "x-10 = 0 or x+2 = 0
\n" ); document.write( "x = 10 or x = -2
\n" ); document.write( "Let's try the 10:
\n" ); document.write( "x^2 = 8(x+2)+4
\n" ); document.write( "10^2 = 8(10+2}+4
\n" ); document.write( "100 = 80+16+4 Correct, this is your answer
\n" ); document.write( "The youngest is 10
\n" ); document.write( "The middle is 10+1 = 11
\n" ); document.write( "The oldest is 10+2 = 12\r
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