document.write( "Question 1130256: Thank you in advance for your help! I was really struggling with this problem:\r
\n" ); document.write( "\n" ); document.write( "Two planes take off from the same airport at the same time using different runways. One plane travels on a bearing S 15 degrees W at 250 miles per hour. The other plane travels on a bearing
\n" ); document.write( " N 75 degrees E at 300 miles per hour. How far are the planes from each other 2 hours after​ takeoff?\r
\n" ); document.write( "\n" ); document.write( "Answer: The distance is approximately ___ miles ( round to the nearest mile as needed)\r
\n" ); document.write( "\n" ); document.write( "THANK YOU AGAIN FOR YOUR HELP!!
\n" ); document.write( "

Algebra.Com's Answer #746941 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
You can use law of cosines which gives you
\n" ); document.write( "opposite side if you have 2 sides and included angle
\n" ); document.write( "------------------
\n" ); document.write( "Draw the picture. You have 120 degrees between
\n" ); document.write( "the flight paths
\n" ); document.write( "1st plane;
\n" ); document.write( "\"+a+=+250%2A2\"
\n" ); document.write( "\"+a+=+500+\" mi
\n" ); document.write( "2nd plane:
\n" ); document.write( "\"+b+=+300%2A2+\"
\n" ); document.write( "\"+b+=+600+\" mi
\n" ); document.write( "----------------------
\n" ); document.write( "\"+c+=+sqrt%28+a%5E2+%2B+b%5E2+-+2%2Aa%2Ab%2Acos%28+theta+%29%29+\"
\n" ); document.write( "\"+c+=+sqrt%28+500%5E2+%2B+600%5E2+-+2%2A500%2A600%2Acos%28+120+%29%29+\"
\n" ); document.write( "\"+c+=+sqrt%28+25%2A10%5E4+%2B+36%2A10%5E4+-+60%2A10%5E4%2A%28+-1%2F2%29+%29+\"
\n" ); document.write( "\"+c+=+sqrt%28+61%2A10%5E4+%2B+30%2A10%5E4+%29+\"
\n" ); document.write( "\"+c+=+10%5E2%2Asqrt%28+91+%29+\"
\n" ); document.write( "\"+c+=+100%2A9.5394\"
\n" ); document.write( "\"+c+=+953.94+\" mi
\n" ); document.write( "--------------------------
\n" ); document.write( "check my math. This looks in the ballpark, since
\n" ); document.write( "it's a little less than \"+500+%2B+600+=+1100+\"\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );