document.write( "Question 1130191: An investment of ​$92 comma 000 was made by a business club. The investment was split into three parts and lasted for one year. The first part of the investment earned​ 8% interest, the second​ 6%, and the third​ 9%. Total interest from the investments was $ 7200.  The interest from the first investment was 4 times the interest from the second. Find the amounts of the three parts of the investment. \n" ); document.write( "
Algebra.Com's Answer #746936 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "The amount of interest from the part at 8% was 4 times the amount of interest from the part at 6%. The 8% rate is 4/3 of the 6% rate; to get 4 times as much interest, using an interest rate that is 4/3 as large, the amount at 8% must be 3 times the amount at 6%. So

\n" ); document.write( "let x = amount at 6%
\n" ); document.write( "then 3x = amount at 8%
\n" ); document.write( "and (92000-4x) = amount at 9%

\n" ); document.write( "The total interest was $7200:

\n" ); document.write( "\".06%28x%29%2B.08%283x%29%2B.09%2892000-4x%29+=+7200\"
\n" ); document.write( "\".06x%2B.24x%2B8280-.36x+=+7200\"
\n" ); document.write( "\"1080+=+.06x\"
\n" ); document.write( "\"x+=+1080%2F.06+=+18000\"

\n" ); document.write( "ANSWER: The amounts invested at each rate were

\n" ); document.write( "6%: x = $18000
\n" ); document.write( "8%: 3x = $54000
\n" ); document.write( "9%: $92000-4x = $20000

\n" ); document.write( "CHECK: \".06%2818000%29%2B.08%2854000%29%2B.09%2820000%29+=+1080%2B4320%2B1800+=+7200\"
\n" ); document.write( "
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