document.write( "Question 1130191: An investment of $92 comma 000 was made by a business club. The investment was split into three parts and lasted for one year. The first part of the investment earned 8% interest, the second 6%, and the third 9%. Total interest from the investments was $ 7200. The interest from the first investment was 4 times the interest from the second. Find the amounts of the three parts of the investment. \n" ); document.write( "
Algebra.Com's Answer #746936 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "The amount of interest from the part at 8% was 4 times the amount of interest from the part at 6%. The 8% rate is 4/3 of the 6% rate; to get 4 times as much interest, using an interest rate that is 4/3 as large, the amount at 8% must be 3 times the amount at 6%. So \n" ); document.write( "let x = amount at 6% \n" ); document.write( "then 3x = amount at 8% \n" ); document.write( "and (92000-4x) = amount at 9% \n" ); document.write( "The total interest was $7200: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "ANSWER: The amounts invested at each rate were \n" ); document.write( "6%: x = $18000 \n" ); document.write( "8%: 3x = $54000 \n" ); document.write( "9%: $92000-4x = $20000 \n" ); document.write( "CHECK: |