document.write( "Question 102627: A girl running at a constant speed of 1.4m/s in a straight line throw a ball directly upward at 4.7 m/s. How far will she travel before the ball drops back into her hand? Ignore air fiction.
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Algebra.Com's Answer #74688 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A girl running at a constant speed of 1.4m/s in a straight line throw a ball directly upward at 4.7 m/s. How far will she travel before the ball drops back into her hand? Ignore air fiction. \n" ); document.write( ": \n" ); document.write( "First find out how long the ball will be in the air, \n" ); document.write( "t = seconds \n" ); document.write( "Gravitational constant: -4.9 m/sec^2 \n" ); document.write( "Upward velocity: +4.7 m/s \n" ); document.write( ": \n" ); document.write( "-4.9t^2 + 4.7t = 0 \n" ); document.write( "t(-4.9t + 4.7) = 0 \n" ); document.write( "Solutions: \n" ); document.write( "t = 0 \n" ); document.write( "and \n" ); document.write( "-4.9t = -4.7 \n" ); document.write( "t = -4.7/-4.9 \n" ); document.write( "t = +.959 seconds \n" ); document.write( ": \n" ); document.write( "Find out how far he runs in .959 sec at a rate of 1.4 m/s \n" ); document.write( ": \n" ); document.write( ".959 * 1.4 = 1.346 m \n" ); document.write( ": \n" ); document.write( "He travels 1.346 meters from the time the ball is thrown until it is caught \n" ); document.write( " |