document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1130211>Question 1130211</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Perform the indicated operation and simplify your answer. Show all steps in factoring.\r<BR>\n" );
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document.write( "	(18n^2)/(4n^2 )&#8901;(9n-90)/3<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #746855 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=746855\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (18n^2)/(4n^2 )&#8901;(9n-90)/3<BR>\n" );
document.write( "(9/2)*9(n-10)/3<BR>\n" );
document.write( "(9/2)* 3(n-10)<BR>\n" );
document.write( "I am assuming the first fraction is multiplied by the second fraction, not that the denominator has two parts.  If it does, then the answer would be (9/2*3(n-10)) or (3/2(n-10)) </SPAN>\n" );
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