document.write( "Question 1130137: A 10cm by 12cm rectangular container contains some water. When a solid metal cube with volume 216cm^3 is placed in the water, the water level comes up level with the top of the cube. In cm, what was the original height of the water in the container?
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Algebra.Com's Answer #746782 by ikleyn(52782)\"\" \"About 
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document.write( "Notice that the side of the cube is  \"root%283%2C216%29\" = 6 cm long.\r\n" );
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document.write( "Let  H  be the original level of the water in the container.\r\n" );
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document.write( "Then the balance equation for the volume is\r\n" );
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document.write( "    10*12*6 = 10*12*H + 216    cubic centimeters,    <<<---===  This formula is self-explanatory\r\n" );
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document.write( "which gives you the solution  \r\n" );
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document.write( "    H = \"%2810%2A12%2A6-216%29%2F%2810%2A12%29\" = 4.2 cm.    ANSWER\r\n" );
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\n" ); document.write( "\n" ); document.write( "If you want to see many other similar solved problems,  look into the lesson\r
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