document.write( "Question 102643This question is from textbook
\n" ); document.write( ": Please help. I don't even know where to begin with this problem:\r
\n" ); document.write( "\n" ); document.write( "Graph the inequality and shade in the correct area of the graph:\r
\n" ); document.write( "\n" ); document.write( "x + 3y is equal to or greater than -2\r
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Algebra.Com's Answer #74672 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
first solve this:\r
\n" ); document.write( "\n" ); document.write( "\"x+%2B+3y+%3E=+-2\"
\n" ); document.write( "\"3y+%3E=+-x+-2\"
\n" ); document.write( "\"y+%3E=+-x%2F3+-+2%2F3\"\r
\n" ); document.write( "\n" ); document.write( "to graf it, you will need two points:\r
\n" ); document.write( "\n" ); document.write( "if \"x+=+0+\" => \"+y+=+-2%2F3\"
\n" ); document.write( " \"x+=+-2+\" \"y+=+0\" \r
\n" ); document.write( "\n" ); document.write( "find these two points on the graph, and draw the line
\n" ); document.write( "everything for \"x+%3E=+-2\" shade; start from the point (x = -2), go to the right, and color dark (or shade it).\r
\n" ); document.write( "\n" ); document.write( "I think the following sample will help: from \"x=-2\" to the right shade the area between the x -axis and the graph from \r
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Solved by pluggable solver: DESCRIBE a linear EQUATION: slope, intercepts, etc
Equation \"1+x+%2B+3+y+=+-2\" describes a sloping line. For any
\n" ); document.write( " equation ax+by+c = 0, slope is \"-a%2Fb+=+-1%2F3\".
  • X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. -2/1 = -2.
  • Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is -2/3 = -0.666666666666667.
  • Slope is -1/3 = -0.333333333333333.
  • Equation in slope-intercept form: y=-0.333333333333333*x+-0.666666666666667.
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